php判断两个坐标的方位角
作者： thtomatic 分类： php笔记 评论: [ 0 ] 条 浏览: [ 1323 ] 次
01 | protected function getAngle($lat1, $lng1, $lat2,$lng2) |
02 | { |
03 | $x1 = $lng1; |
04 | $y1 = $lat1; |
05 | $x2 = $lng2; |
06 | $y2 = $lat2; |
07 | $pi = M_PI; |
08 | $w1 = $y1 / 180 * $pi; |
09 | $j1 = $x1 / 180 * $pi; |
10 | $w2 = $y2 / 180 * $pi; |
11 | $j2 = $x2 / 180 * $pi; |
12 | if ($j1 == $j2) { |
13 | if ($w1 > $w2) |
14 | return 270; // 北半球的情况，南半球忽略 |
15 | else if ($w1 < $w2) |
16 | return 90; |
17 | else |
18 | return -1;// 位置完全相同 |
19 | } |
20 | $ret = 4* pow(sin(($w1 - $w2) / 2), 2)- pow( |
21 | sin(($j1 - $j2) / 2) * (cos($w1) - cos($w2)),2); |
22 | $ret = sqrt($ret); |
23 | $temp = (sin(abs($j1 - $j2) / 2) * (cos($w1) + cos($w2))); |
24 | $ret = $ret / $temp; |
25 | $ret = atan($ret) / $pi * 180; |
26 | if ($j1 > $j2){ // 1为参考点坐标 |
27 | if ($w1 > $w2) |
28 | $ret += 180; |
29 | else |
30 | $ret = 180 - $ret; |
31 | } else if ($w1 > $w2) |
32 | $ret = 360 - $ret; |
33 | return $ret; |
34 | } |
01 | public function getDirection($lat1, $lng1, $lat2,$lng2) { |
02 | $jiaodu = $this->getAngle($lat1, $lng1, $lat2, $lng2); |
03 | if (($jiaodu <= 10) || ($jiaodu > 350)) |
04 | return "东"; |
05 | if (($jiaodu > 10) && ($jiaodu <= 80)) |
06 | return "东北"; |
07 | if (($jiaodu > 80) && ($jiaodu <= 100)) |
08 | return "北"; |
09 | if (($jiaodu > 100) && ($jiaodu <= 170)) |
10 | return "西北"; |
11 | if (($jiaodu > 170) && ($jiaodu <= 190)) |
12 | return "西"; |
13 | if (($jiaodu > 190) && ($jiaodu <= 260)) |
14 | return "西南"; |
15 | if (($jiaodu > 260) && ($jiaodu <= 280)) |
16 | return "南"; |
17 | if (($jiaodu > 280) && ($jiaodu <= 350)) |
18 | return "东南"; |
19 | return ""; |
20 | } |
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